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By C. M. Cuadras, C. R. Rao

The contributions during this quantity, made by means of exceptional statisticians in different frontier components of study in multivariate research, conceal a large box and point out destiny instructions of study. the themes coated contain discriminant research, multidimensional scaling, express info research, correspondence research and biplots, organization research, latent variable types, bootstrap distributions, differential geometry functions and others. lots of the papers suggest generalizations or new functions of multivariate research. This quantity can be of curiosity to statisticians, probabilists, facts analysts and scientists operating within the disciplines akin to biology, biometry, ecology, medication, econometry, psychometry and advertising and marketing. it will likely be a consultant to professors, researchers and graduate scholars looking new and promising strains of statistical study

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Noting that here β{λ,φ) does not de­ pend upon μι and using Lemma 13 we find that the solution set to Q(X) is {φλ\Φλ = (μ, #2(λ), Ω(λ)),μ G Rp}. Moreover, Θ λ = (-oo, 0(/ii)] and ck = p(0) - ViwlogU + n-1n1n2b2}. Thus for Θ < 0(m), ρ(θ) = λθ + cx has the form stated in (b) (iv). The proof of (c) (iv) is similar. That of (d) (iv) follows on observing that b\ = b2 = b\2 = 0 implies θ(η\) = θ(—η2) = 0 and P{n\) = p(-n2) = p(0). Now here condition (2) is that Θ = R. The fact that this (and therefore (l)(b)) holds is immediate for cases (b) to (d) from the above and, for case (a), follows from the explicit forms for Λ and 0λ.

THEOREM 1 Let μ be an eigenvalue of F(n, a) and v = ( υ ι , . . , υη)' be the corresponding eigenvector. Then 1. ξ = 1 — μ/2 is a root of the polynomial ςη(ξ) = ϋη(ξ) + (a — 2) ϋη-\(ξ). 2. The components of v are given by 2 sin(i Θ) Vi = ^2η + where ξ = cos Θ. = 1-υ2η(ξ) ι = 1 , . . , n, For a = 2 we have ςη(ξ) = υη(ξ), hence the roots of ςη(ξ) = 0 are ξ·} = cos (ßj), where n+ 1 For these roots we can see that Uini^j) = — 1 · Thus, the components of the eigenvector v, of C(n) = G(n, 2) are given by Vij = .

Let C have dimension r. The case r = 0 is trivial. Suppose then that 1 < r < m and choose as origin of Rm a point in the relative interior of C. Relative to this origin let M be the subspace spanned by C and N its orthogonal complement. For any ξ in Rm, let £M and §# denote its projection onto M and TV respectively. By hypothesis, 3 λΜ in M such that ρ(θ) = λτΜθΜ + p(0) for all Θ in C. By Proposition 5, A has a nonvertical supporting hyperplane at (0, p(0)). (0)). (#) < λ^# Μ + λ^ · 0 + p(0). That is, (λ Μ — XM)T0M < 0 for all Θ in C.

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